天宇ABCD求破解

ayang0823

已知：可用小区3号4号梯，到期2022年2月6日，电梯可停1楼和23楼，滚动码。
问：可否通楼群及延期，校验码如何破？谢谢各位大神。
+Sector: 0
C3001E20FD08040002637F0DDD3DFC1D
00000000000000000000000000000000
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ABCD06130904FF078069ABCD06130904
+Sector: 1
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ABCD06130904FF078069ABCD06130904
+Sector: 2
F10400000000160206090000000000A1
04000001000000000400000100000000
00000000000000000000000000000000
ABCD06130904FF078069ABCD06130904
+Sector: 3
03040000000000000000000000000000
00000000000000000000000000000000
FFFF0000000000000000000000000000
ABCD06130904FF078069ABCD06130904
+Sector: 4
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00000000000000000000000000000000
ABCD06130904FF078069ABCD06130904
+Sector: 5
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ABCD06130904FF078069ABCD06130904
+Sector: 6
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ABCD06130904FF078069ABCD06130904
+Sector: 7
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ABCD06130904FF078069ABCD06130904
+Sector: 8
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ABCD06130904FF078069ABCD06130904
+Sector: 9
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ABCD06130904FF078069ABCD06130904
+Sector: 10
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ABCD06130904FF078069ABCD06130904
+Sector: 11
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ABCD06130904FF078069ABCD06130904
+Sector: 12
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ABCD06130904FF078069ABCD06130904
+Sector: 13
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ABCD06130904FF078069ABCD06130904
+Sector: 14
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ABCD06130904FF078069ABCD06130904
+Sector: 15
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ABCD06130904FF078069ABCD06130904

周新鹏

校验是卡号第一、二字节和加上第三四字节异或值得出的混合运算，再和固定字节F0异和即为校验数.

王众

谢谢大神！谢谢大神！谢谢大神！

shenhua8110

周新鹏 发表于 2022-1-19 20:58
卡号第一二字节和，加上三四字节异或值，得到数据A，再用A和固定字节F0异或，其值即为校验码。

大神能在讲得详细一点

qd_software

这个贴很有用，感谢！

周新鹏

ayang0823 发表于 2021-2-7 14:40
F10400000000160206090000000000A1   160206是到期日期。F1应该是校验码，不知算法是什么。
0400000100000 ...

卡号第一二字节和，加上三四字节异或值，得到数据A，再用A和固定字节F0异或，其值即为校验码。

周新鹏

校验是卡号第一、二字节和加上第三四字节异或值得出的混合运算，再和固定字节F0异和即为校验数.

ljmdiy

ayang0823 发表于 2021-2-7 14:41
+Sector: 3
03040000000000000000000000000000    应该是3号和4号楼
00000000000000000000000000000000

请教下，如果0304那行都改为0就变为是通卡了吗？谢谢

ayang0823

谢谢大家了谢谢大家了

lyfjdwx

13664600428 发表于 2021-2-10 06:26
是要通楼，不是通小区。

你可以按照上面教你的改的试试，我这边软件改都是花钱改

13664600428

lyfjdwx 发表于 2021-2-9 23:49
楼层全部改成00肯定不行，还有一个功能位也要改

是要通楼，不是通小区。