分享一种鼎博卡密数据的算法

xfx214

鼎博门禁计算卡密keyA:八位卡号异或0c22384e固定字符+30加异或和=密码
keyB：八位卡号异或f3ddc7b1固定字符+cf加异或和=密码


0 扇区
0 区块: 42 58 40 45 1F 08 04 00 02 FC BD 5F 26 8C 53 1D
1 区块: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
2 区块: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
3 区块: FF FF FF FF FF FF FF 07 80 69 FF FF FF FF FF FF


15 扇区
0 区块: 00 13 11 00 00 00 00 00 80 00 00 00 00 00 00 00
1 区块: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
2 区块: 00 00 00 00 00 00 00 00 12 09 0A 14 09 0A 00 00
3 区块: 4E A7 78 0B 30 77 FF 07 80 69 B1 85 87 F4 CF 88

专业做卡的笨蛋

帮帮顶顶！！

xiaozhiwyq

好东西呀过来学习一下

swnning

谢谢楼主分享

风的男人

支持一下:lol

120413695

不错，支持下楼主

胆小的鱼

很好，谢谢分享

胆小的鱼

算了一下：
15 扇区
0 区块: 00 13 11 00 00 00 00 00 80 00 00 00 00 00 00 00
1 区块: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
2 区块: 00 00 00 00 00 00 00 00 12 09 0A 14 09 0A 00 00
3 区块: 4E A7 78 0B 30 77 FF 07 80 69 B1 85 87 F4 CF 88
发现这一个不一样，楼主解释一下呗

xfx214

谢谢指正输入错误，应该是7A

xintao

谢谢楼主分享